The edges of the diameter of a circle are at (-1,2) and (3,-1). Write the equation of the circle in general form.If anyone can also list the steps it would really be appreciated :) I'm very lost on this whole subject at the moment haha

Answer:(x-1)²+ (y-0.5)²=6.25Step-by-step explanation:The standard form of equation of a circle is;(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radiusFinding the mid-point of the given points(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)midpoint= {1/2(-1+3), 1/2(2+-1)}midpoint=(1,0.5)Finding the radius r; the distance from the center to either of the given two pointsApply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then d=√ (-1-1)² +(2-0.5)²d= √ (-2)²+(1.5)²d=√4+2.25⇒√6.25⇒2.5r=2.5Equation of the circle(x-1)² + (y-0.5)²=2.5²(x-1)²+ (y-0.5)²=6.25